I’m stuck on working with your last example. What should I change to pause my worker until user type something in my gui?
Normally if your worker will be waiting a long time you should just stop and start a new worker later. But if you do want it to wait, you can put it in a wait loop (while
self.waiting==True: time.sleep(0.1)) and update the value of self.waiting with a signal from outside.
@martin I’ve been trying to implement this but I really don’t understand how to “update the value of self.waiting with a signal from outside”. Tried defining the signal in the main window by adding a class:
class MainSignals(QObject): wait_signal = pyqtSignal(bool)
and then add
self.signals = MainSignals() in the init of the main window.
I then send the parent (the main window) to the worker but when I connect to the signal with
self.parent.signals.wait_signal.connect(self.set_wait) I get the error:
TypeError: connect() failed between MainSignals.wait_signal[bool] and set_wait()
Hey @Hampus_Nasstrom have a look at this example. It uses methods on the worker to update the values, which are then connected to the signals from the buttons.
from PyQt5.QtWidgets import ( QWidget, QApplication, QProgressBar, QMainWindow, QHBoxLayout, QPushButton ) from PyQt5.QtCore import ( Qt, QObject, pyqtSignal, pyqtSlot, QRunnable, QThreadPool ) import time class WorkerSignals(QObject): progress = pyqtSignal(int) class JobRunner(QRunnable): signals = WorkerSignals() def __init__(self): super().__init__() self.is_paused = False self.is_killed = False @pyqtSlot() def run(self): for n in range(100): self.signals.progress.emit(n + 1) time.sleep(0.1) while self.is_paused: time.sleep(0) if self.is_killed: break def pause(self): self.is_paused = True def resume(self): self.is_paused = False def kill(self): self.is_killed = True class MainWindow(QMainWindow): def __init__(self): super().__init__() # Some buttons w = QWidget() l = QHBoxLayout() w.setLayout(l) btn_stop = QPushButton("Stop") btn_pause = QPushButton("Pause") btn_resume = QPushButton("Resume") l.addWidget(btn_stop) l.addWidget(btn_pause) l.addWidget(btn_resume) self.setCentralWidget(w) # Create a statusbar. self.status = self.statusBar() self.progress = QProgressBar() self.status.addPermanentWidget(self.progress) # Thread runner self.threadpool = QThreadPool() # Create a runner self.runner = JobRunner() self.runner.signals.progress.connect(self.update_progress) self.threadpool.start(self.runner) btn_stop.pressed.connect(self.runner.kill) btn_pause.pressed.connect(self.runner.pause) btn_resume.pressed.connect(self.runner.resume) self.show() def update_progress(self, n): self.progress.setValue(n) app = QApplication() w = MainWindow() app.exec_()
When you run this you’ll see a progress bar moving left to right. If you hit pause it will pause, and resume it will restart. If you press stop it will kill the runner (by exiting the loop).
thank you for your wonderful example. I have a slight problem in using your example. When user closes the GUI without clicking on the Stop button, the thread seems to continue to run. Can advise on the detection of user’s close GUI event and stop all the threads gracefully?
To detect when the app is shutting down you can use the
.aboutToQuit signal on
QApplication. You can connect this up to your workers stop/kill slot to trigger it on shutdown, e.g.
app = QApplication(sys.argv)
Then to connect the worker
If you have many workers, you might prefer to connect this to a handler that will clean up all the workers in one go.
If you have per-window workers, you could also catch the window
closeEvent and stop the workers there.
Thank you for your prompt reply! I followed your code with app = QApplication(sys.argv) and app.aboutToQuit.connect(worker.stop) but I got the worker not defined error. As I used your example above which is
Create a runner
self.runner = JobRunner() self.runner.signals.progress.connect(self.update_progress) self.threadpool.start(self.runner)
so I tried app.aboutToQuit.connect(runner.stop) but my program gave runner is not defined error. When I run my Python program eg. test.py, do I need to run it with an argument? eg. test.py runner?
Sorry for the delay @Albert_Ang I missed your reply. The “not defined” error means that there isn’t a variable with the name you’re using – that either means you’re using the name before it’s been defined, or you’re using the wrong name.
In this case, when you define the window the runner object hasn’t been created yet, so it can’t be connected to. The simplest thing to do is to add an extra method on your window to handle this sort of “shutdown” cleanup, e.g.
def shutdown(self): if self.runner: # set self.runner=None in your __init__ so it's always defined. self.runner.stop()
…and then you can connect to that method, since it’s available as soon as the window is created.
app.aboutToQuit.connect(w.shutdown) # connect to the shutdown method on the window.